Cara Perhitungan Perubahan Biner,Octal,Hexa,Desimal

1. 01000101₂ =........₁₀ ^{(n digit=8)}

= (0 x 2^n-1) + (1 x 2^n-2) +  (0 x 2^n-3) +  (0 x 2^n-4)

   + (0 x 2^n-5) +  (1 x 2^n-6) +  (0 x 2^n-7) +  (1 x 2^n-8)

= (0 x 2⁷) + (1 x 2⁶) + (0 x 2⁵) + (0 x 2⁴) + (0 x 2³)

+ (1 x 2²) + (0 x 2¹) + (1 x 2⁰)

= 0 + 64 + 0 + 0 + 0 + 4 + 0 + 1

= 60₁₀

2. 01110000₂ =........₁₀ ^{(n digit=8)} 

= (0 x 2^n-1) + (1 x 2^n-2) +  (1 x 2^n-3) +  (1 x 2^n-4)

   + (0 x 2^n-5) +  (0 x 2^n-6) +  (0 x 2^n-7) +  (0 x 2^n-8)

= (0 x 2⁷) + (1 x 2⁶) + (1 x 2⁵) + (1 x 2⁴) + (0 x 2³)

+ (0 x 2²) + (0 x 2¹) + (0 x 2⁰)

=  0 + 64 + 32 + 16 + 0 + 0 + 0 + 0

= 112₁₀

3. 01010101₂ =.......₁₀

      = (0x2^n-1) + (1x2^n-2) + (0x2^n-3) + (1x2^n-4) + (0x2^n-5)

       + (1x2^n-6) + (0x2^n-7) + (1x2^n-8)

      = (0x2⁷) + (1x2⁶) + (0x2⁵) + (1x2⁴) + (0x2³)

       + (1x2²) + (0x2¹) + (1x2⁰)

      = 0 + 64 + 0 + 16 + 0 + 4 + 0 + 1

      = 85 ₁₀

4. 01100101₂ =........₁₀

          = (0x2^n-1) + (1x2^n-2) + (1x2^n-3) + (0x2^n-4) + (0x2^n-5) + (1x2^n-6) + (0x2^n-7) + (1x2^n-8)

      = (0x2⁷) + (1x2⁶) + (1x2⁵) + (0x2⁴) + (0x2³) + (1x2²) + (0x2¹) + (1x2⁰)

      = 0 + 64 + 32 + 0 + 0 + 4 + 0 + 1

      = 101₁₀